An ac generator is connected across the terminals of a 3.25-µF capacitor. Determine the frequency at which the capacitive reactance is 375 $\varOmega$.
A)60.0 Hz
B)72.4 Hz
C)85.7 Hz
D)98.9 Hz
E)131 Hz

Question

Quizplus · Accepted Answer

The capacitive reactance $X_c$ is given by $X_c = \frac{1}{2\pi f C}$. Solving for $f$, $f = \frac{1}{2\pi X_c C}$. Substituting $X_c = 375 \, \varOmega$ and $C = 3.25 \times 10^{-6} \, \text{F}$, we find $f \approx 131 \, \text{Hz}$.

An Ac Generator Is Connected Across the Terminals of a 3.25-µF