A 14.0-µF capacitor and a 1480-$\varOmega$ resistor are connected in series to a generator operating at 50.0 Hz and producing an rms voltage of 208 V. What is the average power dissipated in this circuit?
A)190 W
B)28.9 W
C)19.7 W
D)4.18 W
E)zero watts

Question

Quizplus · Accepted Answer

The impedance of the circuit (Z) can be calculated using the formula Z = sqrt(R^2 + X^2) where R is the resistance and X is the reactance. In this case, X = 1/(2πfC) where f is the frequency and C is the capacitance. Plugging in the values, we get X = 1719.44 ohms.

Thus, Z = 1836.66 ohms.

The average power dissipated in the circuit can be calculated using the formula P = V^2/Z, where V is the rms voltage. Plugging in the values, we get P = 28.9 W. Therefore, the correct answer is B.

A 140-µF Capacitor and a 1480- Ω\varOmegaΩ Resistor Are Connected in Series to a Generator Operating at in Series

A 140-µF Capacitor and a 1480- $\varOmega$ Resistor Are Connected in Series to a Generator Operating at in Series