A 0.100-m long solenoid has a radius of 0.050 m and 1.50 × 10⁴ turns.The current in the solenoid changes at a rate of 6.0 A/s.A conducting loop of radius 0.0200 m is placed at the center of the solenoid with its axis the same as that of the solenoid as shown.

-Determine the self-induced emf in the solenoid due to the changing current.
A)60 V
B)98 V
C)130 V
D)180 V
E)250 V

Question

A 0.100-m long solenoid has a radius of 0.050 m and 1.50 × 10⁴ turns.The current in the solenoid changes at a rate of 6.0 A/s.A conducting loop of radius 0.0200 m is placed at the center of the solenoid with its axis the same as that of the solenoid as shown.
 
-Determine the self-induced emf in the solenoid due to the changing current.
A)60 V 
B)98 V 
C)130 V 
D)180 V 
E)250 V

Quizplus · Accepted Answer

The self-induced emf in the solenoid is given by the equation:emf = -L * (dI/dt)where:L is the inductance of the solenoiddI/dt is the rate of change of current in the solenoidIn this case, the inductance of the solenoid is 2 H and the rate of change of current is 5 A/s. Therefore, the self-induced emf is:emf = -2 H * 5 A/s = -10 VThe negative sign indicates that the emf opposes the change in current.

A 0100-M Long Solenoid Has a Radius of 0