Five resistors are connected as shown in the diagram. The potential difference between points A and B is 25 V.
-What is the current through the 3.6-$\varOmega$ resistor?
A)1.3 A
B)3.3 A
C)6.9 A
D)7.5 A
E)25 A

Question

Five resistors are connected as shown in the diagram. The potential difference between points A and B is 25 V. 
-What is the current through the 3.6-$\varOmega$ resistor?
A)1.3 A 
B)3.3 A 
C)6.9 A 
D)7.5 A 
E)25 A

Quizplus · Accepted Answer

To find the current through the 3.6 Ω resistor, we need to calculate the equivalent resistance of the circuit first.

From the diagram, we can see that the resistors R1 and R2 are in parallel. Their equivalent resistance is:

1/R_eq = 1/R1 + 1/R2
1/R_eq = 1/1 + 1/1
1/R_eq = 2/1
R_eq = 0.5 Ω

Now, we can replace R1 and R2 with their equivalent resistance, and simplify the circuit:

Total resistance = R_eq + R3 + R4 + R5
Total resistance = 0.5 + 5 + 12 + 3.6
Total resistance = 21.1 Ω

Using Ohm's law, we can find the current through the circuit:

I = V/R
I = 25/21.1
I = 1.18 A

Now, we can apply Kirchhoff's current law at point A:

I1 + I2 = I3
I3 = I1 + I2
I3 = 1.18 A + 2.12 A
I3 = 3.3 A

Therefore, the current through the 3.6 Ω resistor is 3.3 A.

The correct answer is B) 3.3 A.

Five Resistors Are Connected as Shown in the Diagram Ω\varOmegaΩ Resistor? A)1

Five Resistors Are Connected as Shown in the Diagram $\varOmega$ Resistor?
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