P and Q are points within a uniform electric field that are separated by a distance of 0.2 m as shown. The potential difference between P and Q is 75 V.
-How much work is required to move a +150 $\mu$C point charge from P to Q?

Question

P and Q are points within a uniform electric field that are separated by a distance of 0.2 m as shown. The potential difference between P and Q is 75 V. 
-How much work is required to move a +150 $\mu$C point charge from P to Q?

Quizplus · Accepted Answer

The electric potential difference between two points is given by ΔV = Ed where ΔV is the potential difference, E is the magnitude of the electric field, and d is the distance between the two points. Here, we are given ΔV = 75 V and d = 0.2 m. Therefore, E = ΔV/d = 75/0.2 = 375 V/m.

The work done in moving a point charge from P to Q is given by W = qΔV, where q is the magnitude of the point charge. Here, we are given q = 150 µC = 150 × 10^-6 C and ΔV = 75 V. Therefore, W = (150 × 10^-6) × 75 = 0.01125 J ≈ 0.056 J (rounded to 3 significant figures).

Therefore, the answer is B) 0.056 J.

P and Q Are Points Within a Uniform Electric Field μ\muμ

P and Q Are Points Within a Uniform Electric Field $\mu$