A wave has an amplitude of 0.35 m, a frequency of 1.05 × 10⁶ Hz, and travels in the positive x direction at the speed of light, 3.00 × 10⁸ m/s. Which one of the following equations correctly represents this wave? A)y = 0.35 sin (6.60 × 10⁶t - 0.022x) B)y = 0.35 sin (6.60 × 10⁶t + 0.022x) C)y = 0.35 sin (286t - 1.05 × 10⁶x) D)y = 0.35 sin (286t + 1.05 × 10⁶x) E)y = 0.35 sin (1.05 × 10⁶t + 3.00 × 10⁸x)

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The correct equation for a wave traveling in the positive x direction is:y = A sin (2πft - 2πx/λ)where:A is the amplitude of the wavef is the frequency of the wavet is the timex is the positionλ is the wavelength of the waveIn this case, the amplitude is 0.35 m, the frequency is 1.05 × 10^6 Hz, and the speed of the wave is 3.00 × 10^8 m/s. The wavelength can be calculated using the formula:λ = v/fwhere v is the speed of the wave and f is the frequency.Substituting the given values into the formula, we get:λ = 3.00 × 10^8 m/s / 1.05 × 10^6 Hz = 285.71 mNow we can substitute all of the values into the equation for the wave:y = 0.35 sin (2π(1.05 × 10^6 Hz)t - 2πx/285.71 m)Simplifying, we get:y = 0.35 sin (6.60 × 10^6t - 0.022x)Therefore, the correct answer is A.

A Wave Has an Amplitude of 0