A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter.If the piston that supports the load has a diameter of 0.15 m,approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.
A)250 kg
B)700 kg
C)1400 kg
D)2800 kg
E)5600 kg

Question

Quizplus · Accepted Answer

The force exerted by the hydraulic jack is proportional to the area of the pistons. The area of the smaller piston is π*(0.01)^2, and the area of the larger piston is π*(0.075)^2. The force on the larger piston is (250 N) * (0.075/0.01)^2 = 14062.5 N. Dividing by 9.81 m/s² gives approximately 1433 kg, which is closest to 1400 kg.

A Force of 250 N Is Applied to a Hydraulic