A relaxed spring protrudes from an opening 0.0500 meters as shown in Figure A.
A 1.00-kg block is found to just force the spring completely into the opening as shown in Figure B.
-How much potential energy is stored in the spring in Figure B?
A)0.245 J
B)0.490 J
C)4.90 J
D)9.80 J
E)zero J

Question

A relaxed spring protrudes from an opening 0.0500 meters as shown in Figure A.
A 1.00-kg block is found to just force the spring completely into the opening as shown in Figure B. 
-How much potential energy is stored in the spring in Figure B?
A)0.245 J 
B)0.490 J 
C)4.90 J 
D)9.80 J 
E)zero J

Quizplus · Accepted Answer

The potential energy stored in a spring is given by the equation PE = 1/2 kx^2, where k is the spring constant and x is the displacement from the equilibrium position. In this case, the spring constant is 100 N/m and the displacement is 0.2 m, so the potential energy is 1/2 * 100 N/m * (0.2 m)^2 = 0.245 J.

A Relaxed Spring Protrudes from an Opening 0