A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?
A)2.0 m
B)4.0 m
C)6.0 m
D)8.0 m
E)13 m

Question

Quizplus · Accepted Answer

The car accelerates uniformly, so the distance covered in the first second is 2.0 m. Using the formula for distance under constant acceleration, $s = ut + \frac{1}{2}at^2$, where $u = 0$, $t = 1$, and $s = 2$, we find $a = 4 \, \text{m/s}^2$. In the second second, the total distance covered is $s = \frac{1}{2} \times 4 \times 2^2 = 8 \, \text{m}$. The additional distance in the second second is $8 - 2 = 6 \, \text{m}$.

A Car Starts from Rest and Accelerates at a Constant