A tunnel diode has the following values: IP = 10 mA at VP = 250 mV and IV = 200 μA at VV = 480 mV
Calculate the dynamic resistance of the component.
A) -2.4 kΩ to -25 Ω
B) -23.5 Ω
C) +23.5 Ω
D) 25 Ω to 2.4 kΩ

Question

Quizplus · Accepted Answer

The dynamic resistance (Rd) of a tunnel diode in the negative resistance region can be calculated using the formula Rd = (VV - VP) / (IP - IV), where VV and VP are the voltages at the valley and peak points, and IV and IP are the currents at those points, respectively. Substituting the given values: Rd = (480 mV - 250 mV) / (10 mA - 200 μA) = 230 mV / 9.8 mA = 23.47 Ω, which rounds to -23.5 Ω, considering the negative resistance characteristic of the tunnel diode.

A Tunnel Diode Has the Following Values: IP = 10