A BJT has measured values of IB = 1 mA and IC = 80mA. When IB is varied by ±100 μA, IC changes by ±10 mA. What is the value of dc beta for the device?

Question

Quizplus · Accepted Answer

The DC beta ($\beta_{DC}$) of a BJT is defined as the ratio of the change in collector current ($I_C$) to the change in base current ($I_B$), under DC conditions. Given $I_C = 80mA$ and $I_B = 1mA$, $\beta_{DC} = \frac{I_C}{I_B} = \frac{80mA}{1mA} = 80$.

A BJT Has Measured Values of IB = 1 MA