An E-MOSFET has values of VGSth) = 2 V and IDon) = 8 mA @ VGS = 10 V. What is the value of k for the device?

Question

Quizplus · Accepted Answer

The value of $k$ for an E-MOSFET can be determined using the formula for $I_D$ in the saturation region, which is $I_D = k(V_{GS} - V_{GS(th)})^2$. Given $I_{Don} = 8 mA$ at $V_{GS} = 10 V$ and $V_{GS(th)} = 2 V$, we can solve for $k$. Rearranging the formula to solve for $k$ gives $k = \frac{I_D}{(V_{GS} - V_{GS(th)})^2}$. Substituting the given values, $k = \frac{8 \times 10^{-3}}{(10 - 2)^2} = \frac{8 \times 10^{-3}}{64} = 1.25 \times 10^{-4}$.

An E-MOSFET Has Values of VGSth) = 2 V and IDon)