What is the supply voltage when a 5 kΩ and a 4 kΩ resistor are in series and 6 V is measured across the smaller resistor?
A) 13.5 V
B) 16 V
C) 6 V
D) 12 V

Question

Quizplus · Accepted Answer

The total voltage can be found using the voltage divider rule. The voltage across the 4 kΩ resistor is 6 V, so the ratio of the resistances (4 kΩ out of 9 kΩ total) is used to find the total voltage. The calculation is (5 kΩ + 4 kΩ) / 4 kΩ = 9 kΩ / 4 kΩ times the known voltage across the 4 kΩ resistor, which gives 6 V * (9/4) = 13.5 V.

What Is the Supply Voltage When a 5 KΩ and a 4