50 mA of current flows through a 10 kΩ resistor. How much power is dissipated?
A) 25 mW
B) 5 µW
C) 0.25 µW
D) 25 W

Name: 50 mA of current flows through a 10 kΩ resistor. How much power is dissipated? A) 25 mW B) 5 µW C) 0.25 µW D) 25 W
Brand: Quizplus
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Question

Quizplus · Accepted Answer

Power dissipated in a resistor is calculated using the formula P = I^2 * R. Here, I = 50 mA = 0.05 A and R = 10 kΩ = 10000 Ω. So, P = (0.05)^2 * 10000 = 0.0025 * 10000 = 25 W.

50 MA of Current Flows Through a 10 KΩ Resistor