How many ohms of resistance allows a current of 720 µA to flow, when 3.6 kV is applied?

Question

Quizplus · Accepted Answer

The resistance can be calculated using Ohm's law, which is $V = IR$, where $V$ is the voltage, $I$ is the current, and $R$ is the resistance. Rearranging for $R$, we get $R = \frac{V}{I}$. Substituting the given values, $V = 3.6 kV = 3600 V$ and $I = 720 µA = 720 \times 10^{-6} A$, we find $R = \frac{3600}{720 \times 10^{-6}} = 5 \times 10^{6} \Omega$ or $5 M\Omega$.

How Many Ohms of Resistance Allows a Current of 720