-In the circuit in Figure 16-2, assume that XL = R. The phase angle is 45°.

Name: -In the circuit in Figure 16-2, assume that XL = R. The phase angle is 45°.
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Question

Quizplus · Accepted Answer

When $X_L = R$ in an RL circuit, the phase angle $\theta$ between the voltage and the current is 45° because $\tan(\theta) = \frac{X_L}{R}$, and when $X_L = R$, $\tan(\theta) = 1$, which corresponds to a 45° angle.

-In the Circuit in Figure 16-2, Assume That XL =