Express the impedance of a 10 µF capacitor at 60 Hz in rectangular form.
A) 0 Ω + j265.3 Ω
B) 265.3 Ω - j0 Ω
C) 0 Ω - j0.00377 Ω
D) 0 Ω - j265.3 Ω

Question

Quizplus · Accepted Answer

The impedance of a capacitor in rectangular form is given by $Z = 0 - j\frac{1}{\omega C}$, where $\omega = 2\pi f$ is the angular frequency and $C$ is the capacitance. For a 10 µF capacitor at 60 Hz, $\omega = 2\pi \times 60$, and $C = 10 \times 10^{-6}$ F. Plugging these values in gives $Z = 0 - j\frac{1}{2\pi \times 60 \times 10 \times 10^{-6}} = 0 - j265.3$ Ω.

Express the Impedance of a 10 µF Capacitor at 60