What is the impedance of a RC circuit consisting of a 56 kΩ resistor in series with a 0.033 µF capacitor ata frequency of 450 Hz?
A) 57,016 Ω
B) 45,270 Ω
C) 66,730 Ω
D) 10,730 Ω

Question

Quizplus · Accepted Answer

The impedance $Z$ of a series RC circuit is given by $Z = \sqrt{R^2 + (X_C)^2}$, where $R$ is the resistance and $X_C = \frac{1}{2\pi fC}$ is the capacitive reactance. Here, $R = 56,000 \Omega$, $C = 0.033 \times 10^{-6} F$, and $f = 450 Hz$. Calculating $X_C$ gives $X_C = \frac{1}{2\pi \times 450 \times 0.033 \times 10^{-6}} \approx 106,103 \Omega$. Then, $Z = \sqrt{(56,000)^2 + (106,103)^2} \approx 57,016 \Omega$.

What Is the Impedance of a RC Circuit Consisting of a 56