Which one of the following phasor domain expressions is equivalent to the time domain 50 sinY + 15°)?
A) 35.35 215°
B) 50 215°
C) 70.7 2-15°
D) 70.7 215°

Question

Quizplus · Accepted Answer

The correct phasor domain expression for a time domain signal of the form $A \sin(\omega t + \phi)$ is $A \angle \phi$. Therefore, for $50 \sin(\omega t + 15^\circ)$, the equivalent phasor is $50 \angle 15^\circ$. However, none of the options exactly match this format, suggesting a potential typo in the question or answer choices. Given the options, B) $50 \angle 215^\circ$ is mentioned, but it does not directly correspond to the given time domain expression, indicating a possible error in the question or choices provided.

Which One of the Following Phasor Domain Expressions Is Equivalent