If three capacitors with values of 33 µF, 40 µF and 88 µF were connected in parallel, what is the total capacitance?

Name: If three capacitors with values of 33 µF, 40 µF and 88 µF were connected in parallel, what is the total capacitance?
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Question

Quizplus · Accepted Answer

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances. Therefore, the total capacitance is 33 µF + 40 µF + 88 µF = 161 µF.

If Three Capacitors with Values of 33 µF, 40 µF