What is the amount of flux in an 8-turn coil with 1.5 A of current if the reluctance is .04 x 106 At/Wb?

Name: What is the amount of flux in an 8-turn coil with 1.5 A of current if the reluctance is .04 x 106 At/Wb?
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Question

Quizplus · Accepted Answer

The flux (Φ) in a magnetic circuit is given by the formula Φ = NI/R, where N is the number of turns, I is the current, and R is the reluctance. Substituting the given values: Φ = (8 turns)(1.5 A) / (0.04 x 10^6 At/Wb) = 12 / 40000 = 0.0003 Wb = 300 µWb.

What Is the Amount of Flux in an 8-Turn Coil