A cell has a resting membrane potential of -70 mV and ENa = + 60 mV and EK = - 90 mV. If gNa >0 in this cell,
A) The driving force for Na+ is 60 mV, meaning it will enter the cell
B) The driving force for Na+ is 60 m V, m eaning it will exit the cell
C) The driving force forNa+ is -10 m V, m eaning it will enter the cell
D) The driving force for Na+ is + 10 mV, m eaning it will enter the cell
E) The driving force for Na+ is -130 mV, meaning it will enter the cell
Correct Answer:
Verified
Q1: Repolarization of the nerve during the action
Q2: Opening of the Na+ activation gates in
Q3: The “overshoot” of the action potential means
A)
Q5: In most cells, Increasing gK would cause
A)
Q6: Closing of the K+ at the end
Q7: Opening of the inactivation gate of the
Q8: The Em for a cell is -70
Q9: At rest, the Na channel
A) Activation gates
Q10: In the Hodgkin-Huxley explanation of the action
Q11: Depolarization refers to
A) Making the membrane potential
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