In peas, axial (A) flower position is dominant to terminal (a), tall (L) is dominant to short (l), and yellow (Y) is dominant to green (y). If a plant that is heterozygous for all three traits is allowed to self- fertilize, how many of the offspring would show the dominant phenotype for all three traits?
A) 3/64
B) 32/64
C) 27/64
D) 9/64
E) 64/64

Question

Quizplus · Accepted Answer

The plant in question is heterozygous for all three traits, meaning its genotype is AaLlYy. When it self-fertilizes, the offspring genotypes can be predicted using a Punnett square. For each trait, the heterozygous condition (Aa, Ll, Yy) results in a 3:1 ratio of dominant to recessive phenotypes. When considering all three traits together, the probability of an offspring displaying all dominant phenotypes is (3/4) * (3/4) * (3/4) = 27/64.

In Peas, Axial (A) Flower Position Is Dominant to Terminal