-Refer to the figure above. If fiDC = 100, the minimum value of IB that would cause this transistor to saturate is
A)1 mA.
B)100 µA.
C)0.1 mA.
D)50 µA.

Question

-Refer to the figure above. If fiDC = 100, the minimum value of IB that would cause this transistor to saturate is
A)1 mA. 
B)100 µA. 
C)0.1 mA. 
D)50 µA.

Quizplus · Accepted Answer

To saturate a transistor, the base current (IB) must be sufficient to drive the collector current (IC) to its maximum value. Given fiDC (current gain) is 100, IC = fiDC * IB. For saturation, IC should be at least equal to the maximum load current. Assuming the maximum load current is 10 mA (since it's not specified), IB = 10 mA / 100 = 0.1 mA.

-Refer to the Figure Above