A golfer claims that his average golf score at the course he plays regularly is less than 90. A random sample of 35 rounds of golf was selected and the scores were recorded. Assume that the standard deviation for the population of scores for this golfer is 3.4 and the true population mean for scores for this golfer is 88.2. Using α = 0.05, beta equals -----.

Question

Quizplus · Accepted Answer

The power of the test is 1 - beta. Given the population mean is 88.2, which is less than 90, the null hypothesis is false. The power is calculated using the z-test for means, and the beta value corresponding to the power is 0.0694.

A Golfer Claims That His Average Golf Score at the Course