Bob's golf score at his local course follows the normal distribution with a mean of 92.1 and a standard deviation of 3.8. What is the probability that the score on his next round of golf will be less than 100?

Question

Quizplus · Accepted Answer

To find the probability that Bob's score will be less than 100, we use the Z-score formula: Z = (X - μ) / σ, where X is the score (100), μ is the mean (92.1), and σ is the standard deviation (3.8). Plugging in the numbers: Z = (100 - 92.1) / 3.8 = 2.0789. Looking up this Z-score in a standard normal distribution table or using a calculator gives a probability of approximately 0.9812, indicating a high likelihood that Bob's score will be less than 100.

Bob's Golf Score at His Local Course Follows the Normal