A 6-foot-tall (approximately 183 cm), 20-year-old male weighs 100 kilograms on land but 4 kilograms under water. What is his estimated percent body fatness if the hydrostatic weighing water is 30 degrees Centigrade? (Use provided information from Figure 4.2.) WD at 30º C = 0.99567
RV (men) = [(0.027 x height in cm) + (0.017 x age)] - 3.447
BD = BW % fat = 495 - 450
BW - UW - RV - .1 BD
WD

Question

Quizplus · Accepted Answer

The body density (BD) is calculated using the formula: BD = BW / (BW - UW - RV - 0.1), where BW is body weight on land, UW is underwater weight, RV is residual volume, and WD is water density. Using the given values, the BD is calculated, and then the percent body fat is estimated using the formula: % fat = (495 / BD) - 450. The calculations lead to an estimated body fat percentage of approximately 17 percent.

A 6-Foot-Tall (Approximately 183 Cm), 20-Year-Old Male Weighs 100 Kilograms