A student titrates 50.0 mL of an unknown concentration of HI with 85 mL of a 1.0 M solution of NaOH to reach the equivalence point. What is the pH of the HI solution?

Question

Quizplus · Accepted Answer

The reaction between HI and NaOH is:HI + NaOH → NaI + H2OAt the equivalence point, the moles of HI are equal to the moles of NaOH. Therefore, the concentration of HI is:[HI] = (moles of NaOH) / (volume of HI solution)= (1.0 M) x (85 mL) / (50.0 mL)= 1.7 MThe pH of the HI solution is:pH = -log[H+]= -log(1.7 x 10^-1)= 0.23

A Student Titrates 50