What is the pressure in a 5.80 L container that has 0.545 moles of oxygen gas at 22.0 °C?

Question

Quizplus · Accepted Answer

Using the ideal gas law, $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is the number of moles, $R$ is the ideal gas constant (0.0821 L·atm/(mol·K)), and $T$ is temperature in Kelvin. Convert 22.0 °C to Kelvin (22.0 + 273.15 = 295.15 K) and solve for $P$: $P = \frac{nRT}{V} = \frac{(0.545 \, \text{mol})(0.0821 \, \text{L·atm/(mol·K)})(295.15 \, \text{K})}{5.80 \, \text{L}} \approx 2.28 \, \text{atm}$.

What Is the Pressure in a 5