If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?

Question

Quizplus · Accepted Answer

The balanced chemical equation is:3H2 + N2 → 2NH3From the equation, we can see that 3 moles of hydrogen gas react with 1 mole of nitrogen gas. Therefore, the mole ratio of hydrogen gas to nitrogen gas is 3:1.The molar mass of hydrogen gas is 2 g/mol, and the molar mass of nitrogen gas is 28 g/mol. Therefore, 23.6 g of hydrogen gas is equal to 23.6 g / 2 g/mol = 11.8 moles of hydrogen gas, and 28.3 g of nitrogen gas is equal to 28.3 g / 28 g/mol = 1.01 moles of nitrogen gas.Since the mole ratio of hydrogen gas to nitrogen gas is 3:1, and we have 11.8 moles of hydrogen gas and 1.01 moles of nitrogen gas, the limiting reactant is nitrogen gas. Therefore, the maximum amount of product that can be produced is 2 moles of ammonia, which is equal to 2 moles of ammonia * 17 g/mol = 34.4 g of ammonia.

If 236 G of Hydrogen Gas Reacts with 28