The catalytic decomposition of hydrogen peroxide occurs with the addition of KI. If 10 mL of a saturated KI solution was added to 315 g of hydrogen peroxide, how much oxygen gas would be produced?

Question

Quizplus · Accepted Answer

The decomposition of hydrogen peroxide (H2O2) in the presence of potassium iodide (KI) as a catalyst can be represented by the chemical equation: 2 H2O2 → 2 H2O + O2. This means that from 2 moles of H2O2, 1 mole of O2 is produced. The molar mass of H2O2 is approximately 34 g/mol, and the molar mass of O2 is approximately 32 g/mol. Given 315 g of H2O2, the amount of H2O2 in moles is 315 g / 34 g/mol ≈ 9.26 moles. Since 2 moles of H2O2 produce 1 mole of O2, 9.26 moles of H2O2 would produce approximately 4.63 moles of O2. Therefore, the mass of oxygen gas produced is 4.63 moles * 32 g/mol = 148.16 g, which rounds to 148 g.

The Catalytic Decomposition of Hydrogen Peroxide Occurs with the Addition