Solved

∫sin⁡−3xdx=−1−3sin⁡−4xcos⁡x+−3−1−3∫sin⁡−5xdx\int \sin ^{-3} x d x=\frac{-1}{-3} \sin ^{-4} x \cos x+\frac{-3-1}{-3} \int \sin ^{-5} x d x

Question 43

True/False

∫sin⁡−3xdx=−1−3sin⁡−4xcos⁡x+−3−1−3∫sin⁡−5xdx\int \sin ^{-3} x d x=\frac{-1}{-3} \sin ^{-4} x \cos x+\frac{-3-1}{-3} \int \sin ^{-5} x d x

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q38: Integrate

Q39: Use the table of antiderivatives to

Q40:

Q41:

Q42: Use the table of antiderivatives to

Q44: Find the area of the region

Q45: The following are some of the

Q46: Which of the following gives the

Q47: Compute

Q48: Consider the semicircle of radius 4

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents