In a series RL circuit, ET = 120 V, R = 500 Ω, and XL = 500 Ω. What is the true power?
A) 8.8 W
B) 14.4 W
C) 17.2 W
D) 20.36 W

Question

Quizplus · Accepted Answer

The true power (P) in a series RL circuit is calculated using P = I^2 * R. First, find the impedance Z = √(R^2 + XL^2) = √(500^2 + 500^2) = 707.1 Ω. Then, find the current I = ET / Z = 120 V / 707.1 Ω = 0.1697 A. Finally, calculate P = (0.1697 A)^2 * 500 Ω = 14.4 W.

In a Series RL Circuit, ET = 120 V, R