Of 150 adults who tried a new peach-flavoured peppermint patty, 87 rated it excellent. Of 200 children sampled, 123 rated it excellent. Using the 0.10 level of significance, can we conclude that there is a significant difference in the proportion of adults and the proportion of children who rate the new flavour as excellent? State the decision rule, the value of the test statistic, and your decision. A) Reject if z 1.645 or 1.645, z = -0.66, no difference. C) Reject if z 1.645 or 1.96 or 1.96 or

Question

Of 150 adults who tried a new peach-flavoured peppermint patty, 87 rated it excellent. Of 200 children sampled, 123 rated it excellent. Using the 0.10 level of significance, can we conclude that there is a significant difference in the proportion of adults and the proportion of children who rate the new flavour as excellent? State the decision rule, the value of the test statistic, and your decision. A) Reject if z > 1.645 or < -1.645, z = -0.66, no difference. B) Reject if z > 1.645, z = -0.66, no difference. C) Reject if z > 1.645 or < -1.645, z = -5.28, difference exists. D) Reject if z > 1.96 or < -1.96, z = -0.66, no difference. E) Reject if z > 1.96 or < -1.96, z = -2.26, difference exists.

Quizplus · Accepted Answer

At the 0.10 level of significance, the critical z-values are -1.645 and 1.645 for a two-tailed test. The calculated z-value of -0.66 does not exceed these critical values, indicating no significant difference between the proportions.

Of 150 Adults Who Tried a New Peach-Flavoured Peppermint Patty