Solve the system by the addition method.
-$$\begin{array} { l }
4 x + 6 y = - 42 \
2 x - 4 y = 0
\end{array}$$
$2 x - 4 y = 0$
A) $\{ ( - 6 , - 2 ) \}$
B) $\{ ( - 7 , - 2 ) \}$
C) $\{ ( - 6 , - 3 ) \}$
D) $\varnothing$

Question

Solve the system by the addition method.
-$$\begin{array} { l } 
4 x + 6 y = - 42 \
2 x - 4 y = 0
\end{array}$$
$2 x - 4 y = 0$
A) $\{ ( - 6 , - 2 ) \}$
B) $\{ ( - 7 , - 2 ) \}$
C) $\{ ( - 6 , - 3 ) \}$
D) $\varnothing$

Quizplus · Accepted Answer

The Answer of Solve the system by the addition method.
-$$\begin{array} { l } 
4 x + 6 y = - 42 \
2 x - 4 y = 0
\end{array}$$
$2 x - 4 y = 0$
A) $\{ ( - 6 , - 2 ) \}$
B) $\{ ( - 7 , - 2 ) \}$
C) $\{ ( - 6 , - 3 ) \}$
D) $\varnothing$

Solve the System by the Addition Method 4x+6y=−422x−4y=0\begin{array} { l } 4 x + 6 y = - 42 \\2 x - 4 y = 0\end{array}4x+6y=−422x−4y=0​

Solve the System by the Addition Method $\begin{array} { l } 4 x + 6 y = - 42 \\2 x - 4 y = 0\end{array}$