Solve the problem.
-A twin-engined aircraft can fly 816 miles from city A to city B in 4 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind?
A)34 mph
B)68 mph
C)51 mph
D)17 mph

Question

Quizplus · Accepted Answer

The speed of the wind is 34 mph. To find this, first calculate the speed of the plane in still air and the speed of the wind. Let the speed of the plane in still air be p and the speed of the wind be w. With the wind, the plane's speed is p + w, and against the wind, it's p - w. From the given information, (p + w) = 816/4 = 204 mph, and (p - w) = 816/6 = 136 mph. Solving these equations simultaneously gives w = 34 mph.

Solve the Problem. -A Twin-Engined Aircraft Can Fly 816 Miles from City a from City