Solve the problem.
-Jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. This time it is all nickels and dimes. There are 5 times as many dimes as nickels, and the value of the dimes is $4.50 more Than the value of the nickels. How many nickels and dimes does Jamil have?
A)11 nickels and 55 dimes
B)10 nickels and 50 dimes
C)9 nickels and 45 dimes
D)50 nickels and 10 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. Given that $d = 5n$ and the value difference is $4.50, which translates to 450 cents. The value of dimes is $10d$ cents and the value of nickels is $5n$ cents. The equation for the value difference is $10d - 5n = 450$. Substituting $d = 5n$ gives $50n - 5n = 450$, simplifying to $45n = 450$, which means $n = 10$. Therefore, there are 10 nickels and $5 \times 10 = 50$ dimes.

Solve the Problem. -Jamil Always Throws Loose Change into a Pencil Holder on Pencil