First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$\frac { x - 8 } { 2 x } + 5 = \frac { x + 4 } { x }$
A) No restrictions; $\left\{ \frac { 6 } { 5 } \right\}$
B) $x \neq 0 ; \left\{ \frac { 16 } { 9 } \right\}$
C) $x \neq 0,2 ; \left\{ \frac { 16 } { 9 } \right\}$
D) $x \neq 0 ; \{ - 11 \}$

Question

Quizplus · Accepted Answer

The denominator cannot be zero, so $x \neq 0$. Solving the equation gives $x = \frac { 16 } { 9 }$.

First, Write the Value(s) That Make the Denominator(s) Zero x−82x+5=x+4x\frac { x - 8 } { 2 x } + 5 = \frac { x + 4 } { x }2xx−8​+5=xx+4​

First, Write the Value(s) That Make the Denominator(s) Zero $\frac { x - 8 } { 2 x } + 5 = \frac { x + 4 } { x }$