First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$\frac { 12 } { x - 9 } + 3 = \frac { 6 } { x - 9 }$
A) $x \neq 9 ; \varnothing$
B) $x \neq - 9 ; \{ 15 \}$
C) $x \neq - 9 ; \{ 7 \}$
D) $x \neq 9 ; \{ 7 \}$

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The Answer of First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$\frac { 12 } { x - 9 } + 3 = \frac { 6 } { x - 9 }$
A) $x \neq 9 ; \varnothing$
B) $x \neq - 9 ; \{ 15 \}$
C) $x \neq - 9 ; \{ 7 \}$
D) $x \neq 9 ; \{ 7 \}$

First, Write the Value(s) That Make the Denominator(s) Zero 12x−9+3=6x−9\frac { 12 } { x - 9 } + 3 = \frac { 6 } { x - 9 }x−912​+3=x−96​

First, Write the Value(s) That Make the Denominator(s) Zero $\frac { 12 } { x - 9 } + 3 = \frac { 6 } { x - 9 }$