Solve the equation.
-$\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }$

Question

Quizplus · Accepted Answer

The equation simplifies to an identity that holds for all values of $x$ except those that make the denominators zero, which are $x = -4$ and $x = -3$. However, the original equation is structured in a way that suggests a solution might exist, but upon simplification, it reveals that there are no specific values of $x$ that satisfy it beyond the restrictions imposed by the denominators. Therefore, there are no solutions.

Solve the Equation 1x+4+2x+3=−1x2+7x+12\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }x+41​+x+32​=x2+7x+12−1​

Solve the Equation $\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }$