Solve the problem.
-There are 18 more sophomores than juniors in an 8 AM algebra class. If there are 52 students in this class, find the number of sophomores and the number of juniors in the class.
A)35 sophomores; 17 juniors
B)17 sophomores; 35 juniors
C)52 sophomores; 34 juniors
D)70 sophomores; 34 juniors

Question

Quizplus · Accepted Answer

Let the number of juniors be $j$ and the number of sophomores be $j + 18$. The total number of students is $j + (j + 18) = 52$. Solving for $j$ gives $2j + 18 = 52$, so $2j = 34$, and $j = 17$. Therefore, there are 17 juniors and $17 + 18 = 35$ sophomores.

Solve the Problem. -There Are 18 More Sophomores Than Juniors in an 8