Solve the equation by completing the square.
-$$x ^ { 2 } - 2 x - 3 = 0$$
A) $\{ - \sqrt { 3 } , \sqrt { 3 } \}$
B) $\{ - 3,1 \}$
C) $\{ - 1,3 \}$
D) $\{ - 1 , - 2 \}$

Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $x^2 - 2x = 3$. Add 1 to both sides to complete the square: $(x - 1)^2 = 4$. Solving gives $x - 1 = \pm 2$, so $x = 3$ or $x = -1$. Thus, the solution set is $\{-1, 3\}$.

Solve the Equation by Completing the Square x2−2x−3=0x ^ { 2 } - 2 x - 3 = 0x2−2x−3=0

Solve the Equation by Completing the Square $x ^ { 2 } - 2 x - 3 = 0$