Solve the problem.
-The maximum number of volts, $E$, that can be placed across a resistor is given by the formula $E = \sqrt { P R }$, where $P$ is the number of watts of power that the resistor can absorb and $R$ is the resistance of the resistor in ohms. Solve this equation for $R$. Use the result to determine the resistance of a resistor if $P$ is $\frac { 1 } { 4 }$ watts and $E$ is 60 volts.
A) $\mathrm { R } = \frac { \mathrm { E } ^ { 2 } } { \mathrm { P } ^ { 2 } } ; 57,600 \mathrm { ohms }$
B) $\mathrm { R } = \mathrm { E } ^ { 2 } \mathrm { P } ; 14,400 \mathrm { ohms }$
C) $\mathrm { R } = \mathrm { E } ^ { 2 } \mathrm { P } ^ { 2 } ; 57,600$ ohms
D) $\mathrm { R } = \frac { \mathrm { E } ^ { 2 } } { \mathrm { P } } ; 14,400 \mathrm { ohms }$

Question

Quizplus · Accepted Answer

To solve for $R$, we square both sides of the equation $E = \sqrt{PR}$ to get $E^2 = PR$, and then solve for $R$ by dividing both sides by $P$, resulting in $R = \frac{E^2}{P}$. Substituting $P = \frac{1}{4}$ watts and $E = 60$ volts into this formula gives $R = \frac{60^2}{\frac{1}{4}} = \frac{3600}{\frac{1}{4}} = 14,400$ ohms.

Solve the Problem EEE , That Can Be Placed Across a Resistor Is Given

Solve the Problem $E$ , That Can Be Placed Across a Resistor Is Given