Solve the problem.
-A standard train ticket in a certain city costs $2.50 per ride. People who use the train also have the option of purchasing a frequent-rider pass for $15.75 each month. With the pass, a ticket costs only $1.75 per ride. How Many train rides in a month make the frequent-rider pass a better deal than standard train tickets?
A)23 or more rides
B)21 or more rides
C)22 or more rides
D)20 or more rides

Question

Quizplus · Accepted Answer

To find the break-even point where the frequent-rider pass becomes a better deal, set up an equation comparing the cost of standard tickets to the cost with a pass. Let $x$ be the number of rides. Without the pass, the cost is $2.50x$. With the pass, the cost is $15.75 + 1.75x$. Set them equal to find the break-even point: $2.50x = 15.75 + 1.75x$. Solving for $x$ gives $0.75x = 15.75$, so $x = 21$. Therefore, at 22 rides (the next whole number), the pass is a better deal.

Solve the Problem. -A Standard Train Ticket in a Certain City Costs $2.50