Solve by the quadratic formula. Simplify answers. Use i notation for nonreal complex numbers.
-$$\frac { 1 } { x + 15 } + \frac { 1 } { x } = \frac { 1 } { 10 }$$
A) $x = \frac { - 5 \pm 25 } { 2 }$
B) $x = \frac { 5 \pm 25 } { 2 }$
C) $x = \frac { 35 \pm 25 } { 2 }$
D) $x = \frac { - 35 \pm 25 } { 2 }$

Question

Quizplus · Accepted Answer

The quadratic formula is $x = \frac { -b \pm \sqrt {b^2 - 4ac} } { 2a }$. In this case, $a = 10, b = -15,$ and $c = 1$. Substituting these values into the formula, we get:$$x = \frac { -(-15) \pm \sqrt {(-15)^2 - 4(10)(1)} } { 2(10) }$$$$x = \frac { 15 \pm \sqrt {225 - 40} } { 20 }$$$$x = \frac { 15 \pm \sqrt {185} } { 20 }$$$$x = \frac { 15 \pm 5\sqrt {7} } { 20 }$$$$x = \frac { 3 \pm \sqrt {7} } { 4 }$$

Solve by the Quadratic Formula 1x+15+1x=110\frac { 1 } { x + 15 } + \frac { 1 } { x } = \frac { 1 } { 10 }x+151​+x1​=101​

Solve by the Quadratic Formula $\frac { 1 } { x + 15 } + \frac { 1 } { x } = \frac { 1 } { 10 }$