Write a quadratic equation having the given solutions.
-$- 6,2$
A) $x ^ { 2 } - 12 x - 4 = 0$
B) $x ^ { 2 } + 4 x - 12 = 0$
C) $x ^ { 2 } - 4 x - 12 = 0$
D) $x ^ { 2 } + 12 x - 4 = 0$

Question

Quizplus · Accepted Answer

Given solutions are $-6$ and $2$. The sum of the solutions is $-6 + 2 = -4$ (coefficient of $x$) and their product is $-6 \times 2 = -12$ (constant term). Thus, the quadratic equation is $x^2 - 4x - 12 = 0$.

Write a Quadratic Equation Having the Given Solutions −6,2- 6,2−6,2 A) x2−12x−4=0x ^ { 2 } - 12 x - 4 = 0x2−12x−4=0

Write a Quadratic Equation Having the Given Solutions $- 6,2$ A) $x ^ { 2 } - 12 x - 4 = 0$