Make an appropriate substitution in order to obtain a quadratic equation. Find all complex values for x.
-$$6 x ^ { - 2 } - x ^ { - 1 } - 1 = 0$$
A) $x = \frac { 1 } { 3 } , - \frac { 1 } { 2 }$
B) $x = 3 , - 2$
C) $x = - 3$,
D) $x = - \frac { 1 } { 3 } , -$

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The Answer of Make an appropriate substitution in order to obtain a quadratic equation. Find all complex values for x.
-$$6 x ^ { - 2 } - x ^ { - 1 } - 1 = 0$$
A) $x = \frac { 1 } { 3 } , - \frac { 1 } { 2 }$
B) $x = 3 , - 2$
C) $x = - 3$,
D) $x = - \frac { 1 } { 3 } , -$

Make an Appropriate Substitution in Order to Obtain a Quadratic 6x−2−x−1−1=06 x ^ { - 2 } - x ^ { - 1 } - 1 = 06x−2−x−1−1=0

Make an Appropriate Substitution in Order to Obtain a Quadratic $6 x ^ { - 2 } - x ^ { - 1 } - 1 = 0$