Factor using the trial and error method
-$4 x ^ { 2 } - x - 3$
A) $( 4 x - 1 ) ( x + 3 )$
B) $( 4 x + 3 ) ( x - 1 )$
C) $( 4 x - 3 ) ( x + 1 )$
D) $( 4 x + 1 ) ( x - 3 )$

Question

Quizplus · Accepted Answer

The correct factorization is found by looking for factors of $4x^2$ and $-3$ that when multiplied and added give the middle term $-x$. The factors $4x$ and $x$ for $4x^2$, and $3$ and $-1$ for $-3$, work correctly in the combination $(4x + 3)(x - 1)$, which multiplies out to $4x^2 - x - 3$.

Factor Using the Trial and Error Method - 4x2−x−34 x ^ { 2 } - x - 34x2−x−3

Factor Using the Trial and Error Method
- $4 x ^ { 2 } - x - 3$