Factor as completely as possible. If unfactorable, indicate that the polynomial is prime.
-$$2 x ^ { 2 } - 18 x + 40 = 0$$
A) $x = 0,4,5$
B) $x = 2,4,5$
C) $x = - 4 , - 5$
D) $x = 4,5$

Question

Quizplus · Accepted Answer

The given equation is a quadratic equation, not a list of solutions. To factor it, we look for factors of $2x^2 - 18x + 40$. Factoring out the greatest common factor (GCF) of 2, we get $2(x^2 - 9x + 20)$. Further factoring the quadratic inside the parentheses gives $2(x - 4)(x - 5)$, which means the solutions to the equation $2x^2 - 18x + 40 = 0$ are $x = 4$ and $x = 5$, corresponding to the factors $x - 4 = 0$ and $x - 5 = 0$.

Factor as Completely as Possible 2x2−18x+40=02 x ^ { 2 } - 18 x + 40 = 02x2−18x+40=0

Factor as Completely as Possible $2 x ^ { 2 } - 18 x + 40 = 0$