Solve the problem.
-An object is thrown upward from the top of a 160 -foot building with an initial velocity of 48 feet per second. The height $h$ of the object after $t$ seconds is given by the quadratic equation $h = - 16 t ^ { 2 } + 48 t + 160$. When will the object hit the ground?

Question

Quizplus · Accepted Answer

To find when the object hits the ground, set $h = 0$ and solve the quadratic equation $-16t^2 + 48t + 160 = 0$. Factoring or using the quadratic formula gives $t = 5$ seconds as the positive solution, indicating the time when the object will hit the ground. Negative time is not physically meaningful in this context.

Solve the Problem hhh Of the Object After ttt Seconds Is Given by the Quadratic Equation

Solve the Problem $h$ Of the Object After $t$ Seconds Is Given by the Quadratic Equation